What are the solutions to the equation 11=10x^2-x ?

The solutions to the equation 11=10x^2-x are x= 11/10 ,x=-1

Find the zeros of 11=10x^2-x

The zeros of 11=10x^2-x are x= 11/10 ,x=-1

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11 = 10 x^{2} - x

x = \frac{11}{10}, x = - 1

Decimal Notation

x = 1.1, x = - 1

Solution steps

11 = 10 x^{2} - x

Switch sides

10 x^{2} - x = 11

Move

11

to the left side

10 x^{2} - x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 10 ( - 11 )}{2 \cdot 10}

(- 1)^{2} - 4 \cdot 10 (- 11) = 21

x_{1, 2} = \frac{- ( - 1 ) \pm 21}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 21}{2 \cdot 10}, x_{2} = \frac{- ( - 1 ) - 21}{2 \cdot 10}

x = \frac{- ( - 1 ) + 21}{2 \cdot 10} : \frac{11}{10}

x = \frac{- ( - 1 ) - 21}{2 \cdot 10} : - 1

The solutions to the quadratic equation are:

x = \frac{11}{10}, x = - 1

- 4 x^{2} + 4 x = 0

2 x^{2} + 10 x = 3 x + 15

(x - 7) (x + 8) = 0

x^{2} - 6 + 9 = 0

1 0^{2} = x^{2} + 6^{2}

What are the solutions to the equation 11=10x^2-x ?
The solutions to the equation 11=10x^2-x are x= 11/10 ,x=-1
Find the zeros of 11=10x^2-x
The zeros of 11=10x^2-x are x= 11/10 ,x=-1