What are the solutions to the equation 5x-7x^2=3x+4 ?

The solutions to the equation 5x-7x^2=3x+4 are x= 1/7-i(3sqrt(3))/7 ,x= 1/7+i(3sqrt(3))/7

Find the zeros of 5x-7x^2=3x+4

The zeros of 5x-7x^2=3x+4 are x= 1/7-i(3sqrt(3))/7 ,x= 1/7+i(3sqrt(3))/7

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5 x - 7 x^{2} = 3 x + 4

x = \frac{1}{7} - i \frac{3 3}{7}, x = \frac{1}{7} + i \frac{3 3}{7}

Solution steps

5 x - 7 x^{2} = 3 x + 4

Move

4

to the left side

5 x - 7 x^{2} - 4 = 3 x

Move

3 x

to the left side

- 7 x^{2} + 2 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 7 ) ( - 4 )}{2 ( - 7 )}

Simplify

2^{2} - 4 (- 7) (- 4) : 63 i

x_{1, 2} = \frac{- 2 \pm 6 3 i}{2 ( - 7 )}

Separate the solutions

x_{1} = \frac{- 2 + 6 3 i}{2 ( - 7 )}, x_{2} = \frac{- 2 - 6 3 i}{2 ( - 7 )}

x = \frac{- 2 + 6 3 i}{2 ( - 7 )} : \frac{1}{7} - i \frac{3 3}{7}

x = \frac{- 2 - 6 3 i}{2 ( - 7 )} : \frac{1}{7} + i \frac{3 3}{7}

The solutions to the quadratic equation are:

x = \frac{1}{7} - i \frac{3 3}{7}, x = \frac{1}{7} + i \frac{3 3}{7}

x^{2} + 3 x = 9

s^{2} + 2 s = 0

x^{2} + 5 = 13

4 (3 x - 8)^{2} = 4

\frac{2 x ^{2} + 1}{5} + \frac{x + 3}{10} = 1

What are the solutions to the equation 5x-7x^2=3x+4 ?
The solutions to the equation 5x-7x^2=3x+4 are x= 1/7-i(3sqrt(3))/7 ,x= 1/7+i(3sqrt(3))/7
Find the zeros of 5x-7x^2=3x+4
The zeros of 5x-7x^2=3x+4 are x= 1/7-i(3sqrt(3))/7 ,x= 1/7+i(3sqrt(3))/7