What are the solutions to the equation 2x^2-4x-15=0 ?

The solutions to the equation 2x^2-4x-15=0 are x=(2+sqrt(34))/2 ,x=(2-sqrt(34))/2

Find the zeros of 2x^2-4x-15=0

The zeros of 2x^2-4x-15=0 are x=(2+sqrt(34))/2 ,x=(2-sqrt(34))/2

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2 x^{2} - 4 x - 15 = 0

x = \frac{2 + 34}{2}, x = \frac{2 - 34}{2}

Decimal Notation

x = 3.91547 \dots, x = - 1.91547 \dots

Solution steps

2 x^{2} - 4 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 ( - 15 )}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 (- 15) = 234

x_{1, 2} = \frac{- ( - 4 ) \pm 2 34}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 34}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 2 34}{2 \cdot 2}

x = \frac{- ( - 4 ) + 2 34}{2 \cdot 2} : \frac{2 + 34}{2}

x = \frac{- ( - 4 ) - 2 34}{2 \cdot 2} : \frac{2 - 34}{2}

The solutions to the quadratic equation are:

x = \frac{2 + 34}{2}, x = \frac{2 - 34}{2}

x^{2} - \frac{4}{5} x - 4

a^{2} - a + 1 = 0

6 x^{2} = 13 x + 15

7 - \frac{1}{4} x^{2} - \frac{4}{3} x = 0

2 x^{2} + 4 x + 3

What are the solutions to the equation 2x^2-4x-15=0 ?
The solutions to the equation 2x^2-4x-15=0 are x=(2+sqrt(34))/2 ,x=(2-sqrt(34))/2
Find the zeros of 2x^2-4x-15=0
The zeros of 2x^2-4x-15=0 are x=(2+sqrt(34))/2 ,x=(2-sqrt(34))/2