What are the solutions to the equation x^2+x-18=0 ?

The solutions to the equation x^2+x-18=0 are x=(-1+sqrt(73))/2 ,x=(-1-sqrt(73))/2

Find the zeros of x^2+x-18=0

The zeros of x^2+x-18=0 are x=(-1+sqrt(73))/2 ,x=(-1-sqrt(73))/2

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x^{2} + x - 18 = 0

x = \frac{- 1 + 73}{2}, x = \frac{- 1 - 73}{2}

Decimal Notation

x = 3.77200 \dots, x = - 4.77200 \dots

Solution steps

x^{2} + x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 18) = 73

x_{1, 2} = \frac{- 1 \pm 73}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 73}{2 \cdot 1}, x_{2} = \frac{- 1 - 73}{2 \cdot 1}

x = \frac{- 1 + 73}{2 \cdot 1} : \frac{- 1 + 73}{2}

x = \frac{- 1 - 73}{2 \cdot 1} : \frac{- 1 - 73}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 73}{2}, x = \frac{- 1 - 73}{2}

50 x^{2} - 200 x - 250 = 0

x^{2} + (\frac{3}{4})^{2} = 1

x^{2} - 2 x - 8

x (x - 1) = 1

x^{2} - x - 12 = 0

What are the solutions to the equation x^2+x-18=0 ?
The solutions to the equation x^2+x-18=0 are x=(-1+sqrt(73))/2 ,x=(-1-sqrt(73))/2
Find the zeros of x^2+x-18=0
The zeros of x^2+x-18=0 are x=(-1+sqrt(73))/2 ,x=(-1-sqrt(73))/2