What are the solutions to the equation 50x^2-200x-250=0 ?

The solutions to the equation 50x^2-200x-250=0 are x=5,x=-1

Find the zeros of 50x^2-200x-250=0

The zeros of 50x^2-200x-250=0 are x=5,x=-1

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50 x^{2} - 200 x - 250 = 0

x = 5, x = - 1

Solution steps

50 x^{2} - 200 x - 250 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 200 ) \pm ( - 200 ) ^{2} - 4 \cdot 50 ( - 250 )}{2 \cdot 50}

(- 200)^{2} - 4 \cdot 50 (- 250) = 300

x_{1, 2} = \frac{- ( - 200 ) \pm 300}{2 \cdot 50}

Separate the solutions

x_{1} = \frac{- ( - 200 ) + 300}{2 \cdot 50}, x_{2} = \frac{- ( - 200 ) - 300}{2 \cdot 50}

x = \frac{- ( - 200 ) + 300}{2 \cdot 50} : 5

x = \frac{- ( - 200 ) - 300}{2 \cdot 50} : - 1

The solutions to the quadratic equation are:

x = 5, x = - 1

x^{2} + (\frac{3}{4})^{2} = 1

x^{2} - 2 x - 8

x (x - 1) = 1

x^{2} - x - 12 = 0

4 x^{2} + 5 b x = - b^{2}

What are the solutions to the equation 50x^2-200x-250=0 ?
The solutions to the equation 50x^2-200x-250=0 are x=5,x=-1
Find the zeros of 50x^2-200x-250=0
The zeros of 50x^2-200x-250=0 are x=5,x=-1