What are the solutions to the equation 4x^2+5bx=-b^2 ?

The solutions to the equation 4x^2+5bx=-b^2 are x=-b/4 ,x=-b

Find the zeros of 4x^2+5bx=-b^2

The zeros of 4x^2+5bx=-b^2 are x=-b/4 ,x=-b

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4 x^{2} + 5 b x = - b^{2}

x = - \frac{b}{4}, x = - b

Solution steps

4 x^{2} + 5 b x = - b^{2}

Move

b^{2}

to the left side

4 x^{2} + 5 b x + b^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 b \pm ( 5 b ) ^{2} - 4 \cdot 4 b ^{2}}{2 \cdot 4}

Simplify

(5 b)^{2} - 4 \cdot 4 b^{2} : 3 b

x_{1, 2} = \frac{- 5 b \pm 3 b}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 5 b + 3 b}{2 \cdot 4}, x_{2} = \frac{- 5 b - 3 b}{2 \cdot 4}

x = \frac{- 5 b + 3 b}{2 \cdot 4} : - \frac{b}{4}

x = \frac{- 5 b - 3 b}{2 \cdot 4} : - b

The solutions to the quadratic equation are:

x = - \frac{b}{4}, x = - b

2 x - 3 x^{2} = 5

(3 x + 2)^{2} = 4

x^{2} - 9 x + 15 = 0

135 = (2 y + 3) (2 y - 3)

3 x^{2} - x = 5

What are the solutions to the equation 4x^2+5bx=-b^2 ?
The solutions to the equation 4x^2+5bx=-b^2 are x=-b/4 ,x=-b
Find the zeros of 4x^2+5bx=-b^2
The zeros of 4x^2+5bx=-b^2 are x=-b/4 ,x=-b