What are the solutions to the equation 4x^2-25x=0 ?

The solutions to the equation 4x^2-25x=0 are x= 25/4 ,x=0

Find the zeros of 4x^2-25x=0

The zeros of 4x^2-25x=0 are x= 25/4 ,x=0

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4 x^{2} - 25 x = 0

x = \frac{25}{4}, x = 0

Decimal Notation

x = 6.25, x = 0

Solution steps

4 x^{2} - 25 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 25)^{2} - 4 \cdot 4 \cdot 0 = 25

x_{1, 2} = \frac{- ( - 25 ) \pm 25}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 25 ) + 25}{2 \cdot 4}, x_{2} = \frac{- ( - 25 ) - 25}{2 \cdot 4}

x = \frac{- ( - 25 ) + 25}{2 \cdot 4} : \frac{25}{4}

x = \frac{- ( - 25 ) - 25}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

x = \frac{25}{4}, x = 0

4 x^{2} + 14 x + 12 = 0

7 x^{2} - 56 x = 0

x, x^{2} - x y + y^{2} - 3 = 0

x^{2} - 4 x + 7

36 x^{2} - 18 x = 0

What are the solutions to the equation 4x^2-25x=0 ?
The solutions to the equation 4x^2-25x=0 are x= 25/4 ,x=0
Find the zeros of 4x^2-25x=0
The zeros of 4x^2-25x=0 are x= 25/4 ,x=0