What are the solutions to the equation 2-x-x^2=0 ?

The solutions to the equation 2-x-x^2=0 are x=-2,x=1

Find the zeros of 2-x-x^2=0

The zeros of 2-x-x^2=0 are x=-2,x=1

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2 - x - x^{2} = 0

x = - 2, x = 1

Solution steps

2 - x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} - x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 1 ) \cdot 2}{2 ( - 1 )}

(- 1)^{2} - 4 (- 1) \cdot 2 = 3

x_{1, 2} = \frac{- ( - 1 ) \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 3}{2 ( - 1 )}, x_{2} = \frac{- ( - 1 ) - 3}{2 ( - 1 )}

x = \frac{- ( - 1 ) + 3}{2 ( - 1 )} : - 2

x = \frac{- ( - 1 ) - 3}{2 ( - 1 )} : 1

The solutions to the quadratic equation are:

x = - 2, x = 1

3 a^{2} = - 11 a - 6

4 - x^{2} - 2 x

11 x^{2} + 7 x - 30 = 0

x^{2} + 6 x + 5 = 0

8 x^{2} = - 2 + 17 x

What are the solutions to the equation 2-x-x^2=0 ?
The solutions to the equation 2-x-x^2=0 are x=-2,x=1
Find the zeros of 2-x-x^2=0
The zeros of 2-x-x^2=0 are x=-2,x=1