What are the solutions to the equation z^2-10z+24=0 ?

The solutions to the equation z^2-10z+24=0 are z=6,z=4

Find the zeros of z^2-10z+24=0

The zeros of z^2-10z+24=0 are z=6,z=4

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z^{2} - 10 z + 24 = 0

z = 6, z = 4

Solution steps

z^{2} - 10 z + 24 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 24 = 2

z_{1, 2} = \frac{- ( - 10 ) \pm 2}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 10 ) + 2}{2 \cdot 1}, z_{2} = \frac{- ( - 10 ) - 2}{2 \cdot 1}

z = \frac{- ( - 10 ) + 2}{2 \cdot 1} : 6

z = \frac{- ( - 10 ) - 2}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

z = 6, z = 4

(x - 1)^{2} = 2 x + 6

x^{2} + 2 x - 3

12 m^{2} - 5 m - 2 = 0

16 (1 - 2 x)^{2} - 6 = - 5

x^{2} = 2 (3 x - 4)

What are the solutions to the equation z^2-10z+24=0 ?
The solutions to the equation z^2-10z+24=0 are z=6,z=4
Find the zeros of z^2-10z+24=0
The zeros of z^2-10z+24=0 are z=6,z=4