What are the solutions to the equation -2x^2-4x-2=0 ?

The solutions to the equation -2x^2-4x-2=0 are x=-1

Find the zeros of -2x^2-4x-2=0

The zeros of -2x^2-4x-2=0 are x=-1

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- 2 x^{2} - 4 x - 2 = 0

x = - 1

Solution steps

- 2 x^{2} - 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 2 ) ( - 2 )}{2 ( - 2 )}

(- 4)^{2} - 4 (- 2) (- 2) = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 ( - 2 )}

x = \frac{- ( - 4 )}{2 ( - 2 )}

\frac{- ( - 4 )}{2 ( - 2 )} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

x^{2} = - 2 x

- 12 x^{2} + 8 = 0

8 x^{2} + 5 x - 14 = 0

36 x^{2} + 169 = 0

x, 4 x^{2} + 12 x y + 13 y^{2} = 16

What are the solutions to the equation -2x^2-4x-2=0 ?
The solutions to the equation -2x^2-4x-2=0 are x=-1
Find the zeros of -2x^2-4x-2=0
The zeros of -2x^2-4x-2=0 are x=-1