What are the solutions to the equation -2z^2-10z+20=-3z^2 ?

The solutions to the equation -2z^2-10z+20=-3z^2 are z=5+sqrt(5),z=5-sqrt(5)

Find the zeros of -2z^2-10z+20=-3z^2

The zeros of -2z^2-10z+20=-3z^2 are z=5+sqrt(5),z=5-sqrt(5)

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- 2 z^{2} - 10 z + 20 = - 3 z^{2}

z = 5 + 5, z = 5 - 5

Decimal Notation

z = 7.23606 \dots, z = 2.76393 \dots

Solution steps

- 2 z^{2} - 10 z + 20 = - 3 z^{2}

Move

3 z^{2}

to the left side

z^{2} - 10 z + 20 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 20 = 25

z_{1, 2} = \frac{- ( - 10 ) \pm 2 5}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 10 ) + 2 5}{2 \cdot 1}, z_{2} = \frac{- ( - 10 ) - 2 5}{2 \cdot 1}

z = \frac{- ( - 10 ) + 2 5}{2 \cdot 1} : 5 + 5

z = \frac{- ( - 10 ) - 2 5}{2 \cdot 1} : 5 - 5

The solutions to the quadratic equation are:

z = 5 + 5, z = 5 - 5

3 x^{2} + 29 x + 18 = 0

(x - 8)^{2} + (x - 5)^{2} = (x - 9)^{2}

3 a^{2} - 6 a - 34 = 0

12 x^{2} - 36 = 0

x^{2} - 6 = 190

What are the solutions to the equation -2z^2-10z+20=-3z^2 ?
The solutions to the equation -2z^2-10z+20=-3z^2 are z=5+sqrt(5),z=5-sqrt(5)
Find the zeros of -2z^2-10z+20=-3z^2
The zeros of -2z^2-10z+20=-3z^2 are z=5+sqrt(5),z=5-sqrt(5)