What are the solutions to the equation 3a^2-6a-34=0 ?

The solutions to the equation 3a^2-6a-34=0 are a=(3+sqrt(111))/3 ,a=(3-sqrt(111))/3

Find the zeros of 3a^2-6a-34=0

The zeros of 3a^2-6a-34=0 are a=(3+sqrt(111))/3 ,a=(3-sqrt(111))/3

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3 a^{2} - 6 a - 34 = 0

a = \frac{3 + 111}{3}, a = \frac{3 - 111}{3}

Decimal Notation

a = 4.51188 \dots, a = - 2.51188 \dots

Solution steps

3 a^{2} - 6 a - 34 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 ( - 34 )}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 (- 34) = 2111

a_{1, 2} = \frac{- ( - 6 ) \pm 2 111}{2 \cdot 3}

Separate the solutions

a_{1} = \frac{- ( - 6 ) + 2 111}{2 \cdot 3}, a_{2} = \frac{- ( - 6 ) - 2 111}{2 \cdot 3}

a = \frac{- ( - 6 ) + 2 111}{2 \cdot 3} : \frac{3 + 111}{3}

a = \frac{- ( - 6 ) - 2 111}{2 \cdot 3} : \frac{3 - 111}{3}

The solutions to the quadratic equation are:

a = \frac{3 + 111}{3}, a = \frac{3 - 111}{3}

12 x^{2} - 36 = 0

x^{2} - 6 = 190

(x - 3)^{2} = 8

x^{2} - 9 x + 20 = (x - 4)

2 x^{2} = 81

What are the solutions to the equation 3a^2-6a-34=0 ?
The solutions to the equation 3a^2-6a-34=0 are a=(3+sqrt(111))/3 ,a=(3-sqrt(111))/3
Find the zeros of 3a^2-6a-34=0
The zeros of 3a^2-6a-34=0 are a=(3+sqrt(111))/3 ,a=(3-sqrt(111))/3