What are the solutions to the equation s^2-6s+13=0 ?

The solutions to the equation s^2-6s+13=0 are s=3+2i,s=3-2i

Find the zeros of s^2-6s+13=0

The zeros of s^2-6s+13=0 are s=3+2i,s=3-2i

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s^{2} - 6 s + 13 = 0

s = 3 + 2 i, s = 3 - 2 i

Solution steps

s^{2} - 6 s + 13 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 13 : 4 i

s_{1, 2} = \frac{- ( - 6 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- ( - 6 ) + 4 i}{2 \cdot 1}, s_{2} = \frac{- ( - 6 ) - 4 i}{2 \cdot 1}

s = \frac{- ( - 6 ) + 4 i}{2 \cdot 1} : 3 + 2 i

s = \frac{- ( - 6 ) - 4 i}{2 \cdot 1} : 3 - 2 i

The solutions to the quadratic equation are:

s = 3 + 2 i, s = 3 - 2 i

x^{2} + 10 x + 11 = 0

s^{2} + 4 s + 20

3 x^{2} - x - 12 = 0

(x + 4) (x - 2) = 0

x^{2} + 16 x = 80

What are the solutions to the equation s^2-6s+13=0 ?
The solutions to the equation s^2-6s+13=0 are s=3+2i,s=3-2i
Find the zeros of s^2-6s+13=0
The zeros of s^2-6s+13=0 are s=3+2i,s=3-2i