What are the solutions to the equation 5x^2+2x=3 ?

The solutions to the equation 5x^2+2x=3 are x= 3/5 ,x=-1

Find the zeros of 5x^2+2x=3

The zeros of 5x^2+2x=3 are x= 3/5 ,x=-1

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5 x^{2} + 2 x = 3

x = \frac{3}{5}, x = - 1

Solution steps

5 x^{2} + 2 x = 3

Move

3

to the left side

5 x^{2} + 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 5 ( - 3 )}{2 \cdot 5}

2^{2} - 4 \cdot 5 (- 3) = 8

x_{1, 2} = \frac{- 2 \pm 8}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 2 + 8}{2 \cdot 5}, x_{2} = \frac{- 2 - 8}{2 \cdot 5}

x = \frac{- 2 + 8}{2 \cdot 5} : \frac{3}{5}

x = \frac{- 2 - 8}{2 \cdot 5} : - 1

The solutions to the quadratic equation are:

x = \frac{3}{5}, x = - 1

x, 4 x^{2} - 4 m x + 5 m = 0

- 6 x^{2} + 8 x - 5 = 0

x^{2} - 47 x = 0

x^{2} + 3 x = x + 2

x^{2} - 3 x + 5 = 2 x - 9

What are the solutions to the equation 5x^2+2x=3 ?
The solutions to the equation 5x^2+2x=3 are x= 3/5 ,x=-1
Find the zeros of 5x^2+2x=3
The zeros of 5x^2+2x=3 are x= 3/5 ,x=-1