What are the solutions to the equation x^2+3x=x+2 ?

The solutions to the equation x^2+3x=x+2 are x=-1+sqrt(3),x=-1-sqrt(3)

Find the zeros of x^2+3x=x+2

The zeros of x^2+3x=x+2 are x=-1+sqrt(3),x=-1-sqrt(3)

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x^{2} + 3 x = x + 2

x = - 1 + 3, x = - 1 - 3

Solution steps

x^{2} + 3 x = x + 2

Move

2

to the left side

x^{2} + 3 x - 2 = x

Move

x

to the left side

x^{2} + 2 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 2) = 23

x_{1, 2} = \frac{- 2 \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 3}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 3}{2 \cdot 1}

x = \frac{- 2 + 2 3}{2 \cdot 1} : - 1 + 3

x = \frac{- 2 - 2 3}{2 \cdot 1} : - 1 - 3

The solutions to the quadratic equation are:

x = - 1 + 3, x = - 1 - 3

x^{2} - 3 x + 5 = 2 x - 9

2 (5 x + 9)^{2} + 10 = 28

2 x^{2} + 5 = 5 x^{2} - 37

(x + 3)^{2} - 3 = 49

4 (x^{2} + 6) + 35 x = 0

What are the solutions to the equation x^2+3x=x+2 ?
The solutions to the equation x^2+3x=x+2 are x=-1+sqrt(3),x=-1-sqrt(3)
Find the zeros of x^2+3x=x+2
The zeros of x^2+3x=x+2 are x=-1+sqrt(3),x=-1-sqrt(3)