What are the solutions to the equation 7x^2-31x-20=0 ?

The solutions to the equation 7x^2-31x-20=0 are x=5,x=-4/7

Find the zeros of 7x^2-31x-20=0

The zeros of 7x^2-31x-20=0 are x=5,x=-4/7

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7 x^{2} - 31 x - 20 = 0

x = 5, x = - \frac{4}{7}

Decimal Notation

x = 5, x = - 0.57142 \dots

Solution steps

7 x^{2} - 31 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 31 ) \pm ( - 31 ) ^{2} - 4 \cdot 7 ( - 20 )}{2 \cdot 7}

(- 31)^{2} - 4 \cdot 7 (- 20) = 39

x_{1, 2} = \frac{- ( - 31 ) \pm 39}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 31 ) + 39}{2 \cdot 7}, x_{2} = \frac{- ( - 31 ) - 39}{2 \cdot 7}

x = \frac{- ( - 31 ) + 39}{2 \cdot 7} : 5

x = \frac{- ( - 31 ) - 39}{2 \cdot 7} : - \frac{4}{7}

The solutions to the quadratic equation are:

x = 5, x = - \frac{4}{7}

x^{2} - 0.5 x - 5 = 0

x^{2} + \frac{4}{5} x - 8

25 x^{2} - 5625 = 0

(m - 2)^{2} = 5 - 2 (2 m + 7) + 6^{2} + 2

x^{2} + 7 x - 170 = 0

What are the solutions to the equation 7x^2-31x-20=0 ?
The solutions to the equation 7x^2-31x-20=0 are x=5,x=-4/7
Find the zeros of 7x^2-31x-20=0
The zeros of 7x^2-31x-20=0 are x=5,x=-4/7