What are the solutions to the equation completesquare-x^2+6x-8 ?

The solutions to the equation completesquare-x^2+6x-8 are -(x-3)^2+1

Find the zeros of completesquare-x^2+6x-8

The zeros of completesquare-x^2+6x-8 are -(x-3)^2+1

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complete the square

- x^{2} + 6 x - 8

- (x - 3)^{2} + 1

Solution steps

- x^{2} + 6 x - 8

Write

- x^{2} + 6 x - 8

in the form:

x^{2} + 2 a x + a^{2}

Factor out

- 1

- (x^{2} - 6 x + 8)

2 a = - 6 : a = - 3

Add and subtract

(- 3)^{2}

- (x^{2} - 6 x + 8 + (- 3)^{2} - (- 3)^{2})

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} - 6 x + (- 3)^{2} = (x - 3)^{2}

- ((x - 3)^{2} + 8 - (- 3)^{2})

Simplify

- (x - 3)^{2} + 1

(9 z + \frac{1}{2})^{2} + 61 = 39

- 40 m^{2} + 10 m - 1 = 0

m^{2} - 11 m + 30 = 0

x^{2} - 5 x - 24 = 0

x^{2} + 8 x + 60 = 0

What are the solutions to the equation completesquare-x^2+6x-8 ?
The solutions to the equation completesquare-x^2+6x-8 are -(x-3)^2+1
Find the zeros of completesquare-x^2+6x-8
The zeros of completesquare-x^2+6x-8 are -(x-3)^2+1