What are the solutions to the equation -40m^2+10m-1=0 ?

The solutions to the equation -40m^2+10m-1=0 are m= 1/8-i(sqrt(15))/(40),m= 1/8+i(sqrt(15))/(40)

Find the zeros of -40m^2+10m-1=0

The zeros of -40m^2+10m-1=0 are m= 1/8-i(sqrt(15))/(40),m= 1/8+i(sqrt(15))/(40)

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- 40 m^{2} + 10 m - 1 = 0

m = \frac{1}{8} - i \frac{15}{40}, m = \frac{1}{8} + i \frac{15}{40}

Solution steps

- 40 m^{2} + 10 m - 1 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 40 ) ( - 1 )}{2 ( - 40 )}

Simplify

1 0^{2} - 4 (- 40) (- 1) : 215 i

m_{1, 2} = \frac{- 10 \pm 2 15 i}{2 ( - 40 )}

Separate the solutions

m_{1} = \frac{- 10 + 2 15 i}{2 ( - 40 )}, m_{2} = \frac{- 10 - 2 15 i}{2 ( - 40 )}

m = \frac{- 10 + 2 15 i}{2 ( - 40 )} : \frac{1}{8} - i \frac{15}{40}

m = \frac{- 10 - 2 15 i}{2 ( - 40 )} : \frac{1}{8} + i \frac{15}{40}

The solutions to the quadratic equation are:

m = \frac{1}{8} - i \frac{15}{40}, m = \frac{1}{8} + i \frac{15}{40}

m^{2} - 11 m + 30 = 0

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x^{2} + 8 x + 60 = 0

x, x^{2} - 5 x - 14 = 0

3 y^{2} + 12 y = 0

What are the solutions to the equation -40m^2+10m-1=0 ?
The solutions to the equation -40m^2+10m-1=0 are m= 1/8-i(sqrt(15))/(40),m= 1/8+i(sqrt(15))/(40)
Find the zeros of -40m^2+10m-1=0
The zeros of -40m^2+10m-1=0 are m= 1/8-i(sqrt(15))/(40),m= 1/8+i(sqrt(15))/(40)