What are the solutions to the equation solvefor x,x^2-5x-14=0 ?

The solutions to the equation solvefor x,x^2-5x-14=0 are x=7,x=-2

Find the zeros of solvefor x,x^2-5x-14=0

The zeros of solvefor x,x^2-5x-14=0 are x=7,x=-2

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x, x^{2} - 5 x - 14 = 0

x = 7, x = - 2

Solution steps

x^{2} - 5 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 14) = 9

x_{1, 2} = \frac{- ( - 5 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 9}{2 \cdot 1}

x = \frac{- ( - 5 ) + 9}{2 \cdot 1} : 7

x = \frac{- ( - 5 ) - 9}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 7, x = - 2

3 y^{2} + 12 y = 0

- 8 - 8 p^{2} = - 31

y, x^{2} + y^{2} = 9

x^{2} + 2 x + 0 = 0

y^{2} = 6 y

What are the solutions to the equation solvefor x,x^2-5x-14=0 ?
The solutions to the equation solvefor x,x^2-5x-14=0 are x=7,x=-2
Find the zeros of solvefor x,x^2-5x-14=0
The zeros of solvefor x,x^2-5x-14=0 are x=7,x=-2