What are the solutions to the equation 6x^2-2x+3=0 ?

The solutions to the equation 6x^2-2x+3=0 are x= 1/6+i(sqrt(17))/6 ,x= 1/6-i(sqrt(17))/6

Find the zeros of 6x^2-2x+3=0

The zeros of 6x^2-2x+3=0 are x= 1/6+i(sqrt(17))/6 ,x= 1/6-i(sqrt(17))/6

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6 x^{2} - 2 x + 3 = 0

x = \frac{1}{6} + i \frac{17}{6}, x = \frac{1}{6} - i \frac{17}{6}

Solution steps

6 x^{2} - 2 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 6 \cdot 3}{2 \cdot 6}

Simplify

(- 2)^{2} - 4 \cdot 6 \cdot 3 : 217 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 17 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 17 i}{2 \cdot 6}, x_{2} = \frac{- ( - 2 ) - 2 17 i}{2 \cdot 6}

x = \frac{- ( - 2 ) + 2 17 i}{2 \cdot 6} : \frac{1}{6} + i \frac{17}{6}

x = \frac{- ( - 2 ) - 2 17 i}{2 \cdot 6} : \frac{1}{6} - i \frac{17}{6}

The solutions to the quadratic equation are:

x = \frac{1}{6} + i \frac{17}{6}, x = \frac{1}{6} - i \frac{17}{6}

3 x^{2} + 3 x - 7 = 0

x^{2} - 5 = 44

12 - 6 x^{2} = 0

\frac{1}{2} q^{2} + 20 = 86 - 6 q - 3 q^{2}

(2 x - 3)^{2} - 14 = 2 x (x - 7)

What are the solutions to the equation 6x^2-2x+3=0 ?
The solutions to the equation 6x^2-2x+3=0 are x= 1/6+i(sqrt(17))/6 ,x= 1/6-i(sqrt(17))/6
Find the zeros of 6x^2-2x+3=0
The zeros of 6x^2-2x+3=0 are x= 1/6+i(sqrt(17))/6 ,x= 1/6-i(sqrt(17))/6