What are the solutions to the equation X^2-4X+4=0 ?

The solutions to the equation X^2-4X+4=0 are X=2

Find the zeros of X^2-4X+4=0

The zeros of X^2-4X+4=0 are X=2

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X^{2} - 4 X + 4 = 0

X = 2

Solution steps

X^{2} - 4 X + 4 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 4 = 0

X_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 1}

X = \frac{- ( - 4 )}{2 \cdot 1}

\frac{- ( - 4 )}{2 \cdot 1} = 2

X = 2

The solution to the quadratic equation is:

X = 2

4 (2 t + 3) \geq 2 (11 t + 11)

2 x \leq 6

\frac{2}{5} (2 x - 12) = - 28

\frac{1}{4} - \frac{3}{8}

4 x^{2} = - 16

What are the solutions to the equation X^2-4X+4=0 ?
The solutions to the equation X^2-4X+4=0 are X=2
Find the zeros of X^2-4X+4=0
The zeros of X^2-4X+4=0 are X=2