What are the solutions to the equation 4x^2=-16 ?

The solutions to the equation 4x^2=-16 are x=2i,x=-2i

Find the zeros of 4x^2=-16

The zeros of 4x^2=-16 are x=2i,x=-2i

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4 x^{2} = - 16

x = 2 i, x = - 2 i

Solution steps

4 x^{2} = - 16

Divide both sides by

4

x^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 4, x = - - 4

- 4 = 2 i

- - 4 = - 2 i

x = 2 i, x = - 2 i

16 t^{2} - 16 t + 4 = 0

7 ∣ - 7 n - 7 ∣ - 10 = - 10

\frac{1}{5 ^{- 3}} \cdot \frac{1}{5 ^{6}}

(3 x)^{3} (2 x)^{2}

What are the solutions to the equation 4x^2=-16 ?
The solutions to the equation 4x^2=-16 are x=2i,x=-2i
Find the zeros of 4x^2=-16
The zeros of 4x^2=-16 are x=2i,x=-2i