What are the solutions to the equation 3(2x-5)^2-15=48 ?

The solutions to the equation 3(2x-5)^2-15=48 are x=(sqrt(21)+5)/2 ,x=(-sqrt(21)+5)/2

Find the zeros of 3(2x-5)^2-15=48

The zeros of 3(2x-5)^2-15=48 are x=(sqrt(21)+5)/2 ,x=(-sqrt(21)+5)/2

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3 (2 x - 5)^{2} - 15 = 48

x = \frac{21 + 5}{2}, x = \frac{- 21 + 5}{2}

Decimal Notation

x = 4.79128 \dots, x = 0.20871 \dots

Solution steps

3 (2 x - 5)^{2} - 15 = 48

Move

15

to the right side

3 (2 x - 5)^{2} = 63

Divide both sides by

3

(2 x - 5)^{2} = 21

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 5 = 21 : x = \frac{21 + 5}{2}

Solve

2 x - 5 = - 21 : x = \frac{- 21 + 5}{2}

The solutions to the quadratic equation are:

x = \frac{21 + 5}{2}, x = \frac{- 21 + 5}{2}

- 3 x^{2} - 3 x - 9 = - 2

2 x^{2} + 10 x + 4 = 0

4 x^{2} + 6 x + 3 = 0

x^{2} + 4 x - 13 = 0

x^{2} + 12 x = - 20

What are the solutions to the equation 3(2x-5)^2-15=48 ?
The solutions to the equation 3(2x-5)^2-15=48 are x=(sqrt(21)+5)/2 ,x=(-sqrt(21)+5)/2
Find the zeros of 3(2x-5)^2-15=48
The zeros of 3(2x-5)^2-15=48 are x=(sqrt(21)+5)/2 ,x=(-sqrt(21)+5)/2