What are the solutions to the equation -3x^2-3x-9=-2 ?

The solutions to the equation -3x^2-3x-9=-2 are x=-1/2-i(5sqrt(3))/6 ,x=-1/2+i(5sqrt(3))/6

Find the zeros of -3x^2-3x-9=-2

The zeros of -3x^2-3x-9=-2 are x=-1/2-i(5sqrt(3))/6 ,x=-1/2+i(5sqrt(3))/6

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- 3 x^{2} - 3 x - 9 = - 2

x = - \frac{1}{2} - i \frac{5 3}{6}, x = - \frac{1}{2} + i \frac{5 3}{6}

Solution steps

- 3 x^{2} - 3 x - 9 = - 2

Move

2

to the left side

- 3 x^{2} - 3 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 3 ) ( - 7 )}{2 ( - 3 )}

Simplify

(- 3)^{2} - 4 (- 3) (- 7) : 53 i

x_{1, 2} = \frac{- ( - 3 ) \pm 5 3 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 5 3 i}{2 ( - 3 )}, x_{2} = \frac{- ( - 3 ) - 5 3 i}{2 ( - 3 )}

x = \frac{- ( - 3 ) + 5 3 i}{2 ( - 3 )} : - \frac{1}{2} - i \frac{5 3}{6}

x = \frac{- ( - 3 ) - 5 3 i}{2 ( - 3 )} : - \frac{1}{2} + i \frac{5 3}{6}

The solutions to the quadratic equation are:

x = - \frac{1}{2} - i \frac{5 3}{6}, x = - \frac{1}{2} + i \frac{5 3}{6}

2 x^{2} + 10 x + 4 = 0

4 x^{2} + 6 x + 3 = 0

x^{2} + 4 x - 13 = 0

x^{2} + 12 x = - 20

10 p^{2} - 2 p + 12 = 2

What are the solutions to the equation -3x^2-3x-9=-2 ?
The solutions to the equation -3x^2-3x-9=-2 are x=-1/2-i(5sqrt(3))/6 ,x=-1/2+i(5sqrt(3))/6
Find the zeros of -3x^2-3x-9=-2
The zeros of -3x^2-3x-9=-2 are x=-1/2-i(5sqrt(3))/6 ,x=-1/2+i(5sqrt(3))/6