What are the solutions to the equation 10p^2-2p+12=2 ?

The solutions to the equation 10p^2-2p+12=2 are p= 1/10+i(3sqrt(11))/(10),p= 1/10-i(3sqrt(11))/(10)

Find the zeros of 10p^2-2p+12=2

The zeros of 10p^2-2p+12=2 are p= 1/10+i(3sqrt(11))/(10),p= 1/10-i(3sqrt(11))/(10)

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10 p^{2} - 2 p + 12 = 2

p = \frac{1}{10} + i \frac{3 11}{10}, p = \frac{1}{10} - i \frac{3 11}{10}

Solution steps

10 p^{2} - 2 p + 12 = 2

Move

2

to the left side

10 p^{2} - 2 p + 10 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 10 \cdot 10}{2 \cdot 10}

Simplify

(- 2)^{2} - 4 \cdot 10 \cdot 10 : 611 i

p_{1, 2} = \frac{- ( - 2 ) \pm 6 11 i}{2 \cdot 10}

Separate the solutions

p_{1} = \frac{- ( - 2 ) + 6 11 i}{2 \cdot 10}, p_{2} = \frac{- ( - 2 ) - 6 11 i}{2 \cdot 10}

p = \frac{- ( - 2 ) + 6 11 i}{2 \cdot 10} : \frac{1}{10} + i \frac{3 11}{10}

p = \frac{- ( - 2 ) - 6 11 i}{2 \cdot 10} : \frac{1}{10} - i \frac{3 11}{10}

The solutions to the quadratic equation are:

p = \frac{1}{10} + i \frac{3 11}{10}, p = \frac{1}{10} - i \frac{3 11}{10}

x^{2} - 5 x = 3

x^{2} - 12 x + 35 = 1760

12 x^{2} + 4 = 0

2 x \cdot x = 72

x^{2} - 3 x + 13 = 0

What are the solutions to the equation 10p^2-2p+12=2 ?
The solutions to the equation 10p^2-2p+12=2 are p= 1/10+i(3sqrt(11))/(10),p= 1/10-i(3sqrt(11))/(10)
Find the zeros of 10p^2-2p+12=2
The zeros of 10p^2-2p+12=2 are p= 1/10+i(3sqrt(11))/(10),p= 1/10-i(3sqrt(11))/(10)