What are the solutions to the equation x^2-5x=3 ?

The solutions to the equation x^2-5x=3 are x=(5+sqrt(37))/2 ,x=(5-sqrt(37))/2

Find the zeros of x^2-5x=3

The zeros of x^2-5x=3 are x=(5+sqrt(37))/2 ,x=(5-sqrt(37))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 5 x = 3

x = \frac{5 + 37}{2}, x = \frac{5 - 37}{2}

Solution steps

x^{2} - 5 x = 3

Move

3

to the left side

x^{2} - 5 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 3) = 37

x_{1, 2} = \frac{- ( - 5 ) \pm 37}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 37}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 37}{2 \cdot 1}

x = \frac{- ( - 5 ) + 37}{2 \cdot 1} : \frac{5 + 37}{2}

x = \frac{- ( - 5 ) - 37}{2 \cdot 1} : \frac{5 - 37}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 37}{2}, x = \frac{5 - 37}{2}

x^{2} - 12 x + 35 = 1760

12 x^{2} + 4 = 0

2 x \cdot x = 72

x^{2} - 3 x + 13 = 0

6 x^{2} - 23 x + 20 = 0

What are the solutions to the equation x^2-5x=3 ?
The solutions to the equation x^2-5x=3 are x=(5+sqrt(37))/2 ,x=(5-sqrt(37))/2
Find the zeros of x^2-5x=3
The zeros of x^2-5x=3 are x=(5+sqrt(37))/2 ,x=(5-sqrt(37))/2