What are the solutions to the equation x^2-12x+35=1760 ?

The solutions to the equation x^2-12x+35=1760 are x=6+sqrt(1761),x=6-sqrt(1761)

Find the zeros of x^2-12x+35=1760

The zeros of x^2-12x+35=1760 are x=6+sqrt(1761),x=6-sqrt(1761)

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x^{2} - 12 x + 35 = 1760

x = 6 + 1761, x = 6 - 1761

Decimal Notation

x = 47.96427 \dots, x = - 35.96427 \dots

Solution steps

x^{2} - 12 x + 35 = 1760

Move

1760

to the left side

x^{2} - 12 x - 1725 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot ( - 1725 )}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot (- 1725) = 21761

x_{1, 2} = \frac{- ( - 12 ) \pm 2 1761}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 1761}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 2 1761}{2 \cdot 1}

x = \frac{- ( - 12 ) + 2 1761}{2 \cdot 1} : 6 + 1761

x = \frac{- ( - 12 ) - 2 1761}{2 \cdot 1} : 6 - 1761

The solutions to the quadratic equation are:

x = 6 + 1761, x = 6 - 1761

12 x^{2} + 4 = 0

2 x \cdot x = 72

x^{2} - 3 x + 13 = 0

6 x^{2} - 23 x + 20 = 0

- 2 x^{2} + 10 x = 0

What are the solutions to the equation x^2-12x+35=1760 ?
The solutions to the equation x^2-12x+35=1760 are x=6+sqrt(1761),x=6-sqrt(1761)
Find the zeros of x^2-12x+35=1760
The zeros of x^2-12x+35=1760 are x=6+sqrt(1761),x=6-sqrt(1761)