What are the solutions to the equation 6+4x^2=0 ?

The solutions to the equation 6+4x^2=0 are x=sqrt(3/2)i,x=-sqrt(3/2)i

Find the zeros of 6+4x^2=0

The zeros of 6+4x^2=0 are x=sqrt(3/2)i,x=-sqrt(3/2)i

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6 + 4 x^{2} = 0

x = \frac{3}{2} i, x = - \frac{3}{2} i

Solution steps

6 + 4 x^{2} = 0

Move

6

to the right side

4 x^{2} = - 6

Divide both sides by

4

x^{2} = - \frac{3}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{3}{2}, x = - - \frac{3}{2}

- \frac{3}{2} = \frac{3}{2} i

- - \frac{3}{2} = - \frac{3}{2} i

x = \frac{3}{2} i, x = - \frac{3}{2} i

x^{2} - 10 x = 75

x^{2} + 14 x - 1 = 0

2 (x + 1)^{2} + 3 = 21

13 = \frac{8}{3} (4 x + 9) 38 (4 x + 9)

4 x^{2} - 4 x + 4 = 0

What are the solutions to the equation 6+4x^2=0 ?
The solutions to the equation 6+4x^2=0 are x=sqrt(3/2)i,x=-sqrt(3/2)i
Find the zeros of 6+4x^2=0
The zeros of 6+4x^2=0 are x=sqrt(3/2)i,x=-sqrt(3/2)i