What are the solutions to the equation 2(x+1)^2+3=21 ?

The solutions to the equation 2(x+1)^2+3=21 are x=2,x=-4

Find the zeros of 2(x+1)^2+3=21

The zeros of 2(x+1)^2+3=21 are x=2,x=-4

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2 (x + 1)^{2} + 3 = 21

x = 2, x = - 4

Solution steps

2 (x + 1)^{2} + 3 = 21

Move

3

to the right side

2 (x + 1)^{2} = 18

Divide both sides by

2

(x + 1)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 9 : x = 2

Solve

x + 1 = - 9 : x = - 4

The solutions to the quadratic equation are:

x = 2, x = - 4

13 = \frac{8}{3} (4 x + 9) 38 (4 x + 9)

4 x^{2} - 4 x + 4 = 0

x, y^{2} - x^{2} = 0

x^{2} + x = 9

x^{2} - 1.7 x + 0.7 = 0

What are the solutions to the equation 2(x+1)^2+3=21 ?
The solutions to the equation 2(x+1)^2+3=21 are x=2,x=-4
Find the zeros of 2(x+1)^2+3=21
The zeros of 2(x+1)^2+3=21 are x=2,x=-4