What are the solutions to the equation x^2+x=9 ?

The solutions to the equation x^2+x=9 are x=(-1+sqrt(37))/2 ,x=(-1-sqrt(37))/2

Find the zeros of x^2+x=9

The zeros of x^2+x=9 are x=(-1+sqrt(37))/2 ,x=(-1-sqrt(37))/2

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x^{2} + x = 9

x = \frac{- 1 + 37}{2}, x = \frac{- 1 - 37}{2}

Solution steps

x^{2} + x = 9

Move

9

to the left side

x^{2} + x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 9) = 37

x_{1, 2} = \frac{- 1 \pm 37}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 37}{2 \cdot 1}, x_{2} = \frac{- 1 - 37}{2 \cdot 1}

x = \frac{- 1 + 37}{2 \cdot 1} : \frac{- 1 + 37}{2}

x = \frac{- 1 - 37}{2 \cdot 1} : \frac{- 1 - 37}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 37}{2}, x = \frac{- 1 - 37}{2}

x^{2} - 1.7 x + 0.7 = 0

2 x^{2} + 20 x - 14 = 0

x^{2} + 6 x + 0 = 0

\frac{1}{2} x^{2} = - 5

3 x^{2} + 12 x + 5

What are the solutions to the equation x^2+x=9 ?
The solutions to the equation x^2+x=9 are x=(-1+sqrt(37))/2 ,x=(-1-sqrt(37))/2
Find the zeros of x^2+x=9
The zeros of x^2+x=9 are x=(-1+sqrt(37))/2 ,x=(-1-sqrt(37))/2