What are the solutions to the equation 2x^2+20x-14=0 ?

The solutions to the equation 2x^2+20x-14=0 are x=-5+4sqrt(2),x=-5-4sqrt(2)

Find the zeros of 2x^2+20x-14=0

The zeros of 2x^2+20x-14=0 are x=-5+4sqrt(2),x=-5-4sqrt(2)

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2 x^{2} + 20 x - 14 = 0

x = - 5 + 42, x = - 5 - 42

Solution steps

2 x^{2} + 20 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 2 ( - 14 )}{2 \cdot 2}

2 0^{2} - 4 \cdot 2 (- 14) = 162

x_{1, 2} = \frac{- 20 \pm 16 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 20 + 16 2}{2 \cdot 2}, x_{2} = \frac{- 20 - 16 2}{2 \cdot 2}

x = \frac{- 20 + 16 2}{2 \cdot 2} : - 5 + 42

x = \frac{- 20 - 16 2}{2 \cdot 2} : - 5 - 42

The solutions to the quadratic equation are:

x = - 5 + 42, x = - 5 - 42

x^{2} + 6 x + 0 = 0

\frac{1}{2} x^{2} = - 5

3 x^{2} + 12 x + 5

0 = 7 x^{2} + 21

x^{2} + 6 x + 8 = 2

What are the solutions to the equation 2x^2+20x-14=0 ?
The solutions to the equation 2x^2+20x-14=0 are x=-5+4sqrt(2),x=-5-4sqrt(2)
Find the zeros of 2x^2+20x-14=0
The zeros of 2x^2+20x-14=0 are x=-5+4sqrt(2),x=-5-4sqrt(2)