What are the solutions to the equation x^2+6x+8=2 ?

The solutions to the equation x^2+6x+8=2 are x=-3+sqrt(3),x=-3-sqrt(3)

Find the zeros of x^2+6x+8=2

The zeros of x^2+6x+8=2 are x=-3+sqrt(3),x=-3-sqrt(3)

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x^{2} + 6 x + 8 = 2

x = - 3 + 3, x = - 3 - 3

Solution steps

x^{2} + 6 x + 8 = 2

Move

2

to the left side

x^{2} + 6 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 6 = 23

x_{1, 2} = \frac{- 6 \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 3}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 3}{2 \cdot 1}

x = \frac{- 6 + 2 3}{2 \cdot 1} : - 3 + 3

x = \frac{- 6 - 2 3}{2 \cdot 1} : - 3 - 3

The solutions to the quadratic equation are:

x = - 3 + 3, x = - 3 - 3

3 (x + 2)^{2} + 4 = 13

x, 9 x^{2} + 6 y^{2} + 4 x y - y + 2 = 0

y, z = y x^{6} - 3 x + 8 x^{2} y^{2} - y^{2}

2 x^{2} - 4 x - 10 = 0

2 x^{2} - 2 = - 3 x

What are the solutions to the equation x^2+6x+8=2 ?
The solutions to the equation x^2+6x+8=2 are x=-3+sqrt(3),x=-3-sqrt(3)
Find the zeros of x^2+6x+8=2
The zeros of x^2+6x+8=2 are x=-3+sqrt(3),x=-3-sqrt(3)