What are the solutions to the equation 2x^2-4x-10=0 ?

The solutions to the equation 2x^2-4x-10=0 are x=1+sqrt(6),x=1-sqrt(6)

Find the zeros of 2x^2-4x-10=0

The zeros of 2x^2-4x-10=0 are x=1+sqrt(6),x=1-sqrt(6)

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2 x^{2} - 4 x - 10 = 0

x = 1 + 6, x = 1 - 6

Solution steps

2 x^{2} - 4 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 (- 10) = 46

x_{1, 2} = \frac{- ( - 4 ) \pm 4 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 6}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 4 6}{2 \cdot 2}

x = \frac{- ( - 4 ) + 4 6}{2 \cdot 2} : 1 + 6

x = \frac{- ( - 4 ) - 4 6}{2 \cdot 2} : 1 - 6

The solutions to the quadratic equation are:

x = 1 + 6, x = 1 - 6

2 x^{2} - 2 = - 3 x

- 5 z^{2} - 10 z + 1 = - 6 z^{2}

6 x + 3 = 2 x^{2}

x^{2} - \frac{4}{5} x - 1

z^{2} - 2 z

What are the solutions to the equation 2x^2-4x-10=0 ?
The solutions to the equation 2x^2-4x-10=0 are x=1+sqrt(6),x=1-sqrt(6)
Find the zeros of 2x^2-4x-10=0
The zeros of 2x^2-4x-10=0 are x=1+sqrt(6),x=1-sqrt(6)