What are the solutions to the equation x^2-13x-36=0 ?

The solutions to the equation x^2-13x-36=0 are x=(13+sqrt(313))/2 ,x=(13-sqrt(313))/2

Find the zeros of x^2-13x-36=0

The zeros of x^2-13x-36=0 are x=(13+sqrt(313))/2 ,x=(13-sqrt(313))/2

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x^{2} - 13 x - 36 = 0

x = \frac{13 + 313}{2}, x = \frac{13 - 313}{2}

Solution steps

x^{2} - 13 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot (- 36) = 313

x_{1, 2} = \frac{- ( - 13 ) \pm 313}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 313}{2 \cdot 1}, x_{2} = \frac{- ( - 13 ) - 313}{2 \cdot 1}

x = \frac{- ( - 13 ) + 313}{2 \cdot 1} : \frac{13 + 313}{2}

x = \frac{- ( - 13 ) - 313}{2 \cdot 1} : \frac{13 - 313}{2}

The solutions to the quadratic equation are:

x = \frac{13 + 313}{2}, x = \frac{13 - 313}{2}

x^{2} + 10 = 85

y, y^{2} = x^{3}

4 x^{2} + 19 x + 19 = 0

4 x^{2} + 27 = - 20 x

x^{2} - 2 x + 1

What are the solutions to the equation x^2-13x-36=0 ?
The solutions to the equation x^2-13x-36=0 are x=(13+sqrt(313))/2 ,x=(13-sqrt(313))/2
Find the zeros of x^2-13x-36=0
The zeros of x^2-13x-36=0 are x=(13+sqrt(313))/2 ,x=(13-sqrt(313))/2