What are the solutions to the equation 4x^2+27=-20x ?

The solutions to the equation 4x^2+27=-20x are x=-5/2+i(sqrt(2))/2 ,x=-5/2-i(sqrt(2))/2

Find the zeros of 4x^2+27=-20x

The zeros of 4x^2+27=-20x are x=-5/2+i(sqrt(2))/2 ,x=-5/2-i(sqrt(2))/2

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4 x^{2} + 27 = - 20 x

x = - \frac{5}{2} + i \frac{2}{2}, x = - \frac{5}{2} - i \frac{2}{2}

Solution steps

4 x^{2} + 27 = - 20 x

Move

20 x

to the left side

4 x^{2} + 27 + 20 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 20 x + 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 4 \cdot 27}{2 \cdot 4}

Simplify

2 0^{2} - 4 \cdot 4 \cdot 27 : 42 i

x_{1, 2} = \frac{- 20 \pm 4 2 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 20 + 4 2 i}{2 \cdot 4}, x_{2} = \frac{- 20 - 4 2 i}{2 \cdot 4}

x = \frac{- 20 + 4 2 i}{2 \cdot 4} : - \frac{5}{2} + i \frac{2}{2}

x = \frac{- 20 - 4 2 i}{2 \cdot 4} : - \frac{5}{2} - i \frac{2}{2}

The solutions to the quadratic equation are:

x = - \frac{5}{2} + i \frac{2}{2}, x = - \frac{5}{2} - i \frac{2}{2}

x^{2} - 2 x + 1

9.08 = 0.001 (0.723 x^{2} + 15.418 x + 607.733)

(6 a + 2) (8 a + 7) = 0

x^{2} - 9 x = 0

2 (5 x + 7)^{2} - 13 = 33

What are the solutions to the equation 4x^2+27=-20x ?
The solutions to the equation 4x^2+27=-20x are x=-5/2+i(sqrt(2))/2 ,x=-5/2-i(sqrt(2))/2
Find the zeros of 4x^2+27=-20x
The zeros of 4x^2+27=-20x are x=-5/2+i(sqrt(2))/2 ,x=-5/2-i(sqrt(2))/2