What are the solutions to the equation x^2+14x+38=0 ?

The solutions to the equation x^2+14x+38=0 are x=-7+sqrt(11),x=-7-sqrt(11)

Find the zeros of x^2+14x+38=0

The zeros of x^2+14x+38=0 are x=-7+sqrt(11),x=-7-sqrt(11)

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x^{2} + 14 x + 38 = 0

x = - 7 + 11, x = - 7 - 11

Solution steps

x^{2} + 14 x + 38 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 38}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 38 = 211

x_{1, 2} = \frac{- 14 \pm 2 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 2 11}{2 \cdot 1}, x_{2} = \frac{- 14 - 2 11}{2 \cdot 1}

x = \frac{- 14 + 2 11}{2 \cdot 1} : - 7 + 11

x = \frac{- 14 - 2 11}{2 \cdot 1} : - 7 - 11

The solutions to the quadratic equation are:

x = - 7 + 11, x = - 7 - 11

x^{2} - (m + 7) x + 25 = 0

15 x^{2} - 31 x + 10 = 0

2 w^{2} + 29 = - 21

s^{2} + 8 s + 16 = 0

(21 - y)^{2} + y^{2} = 221

What are the solutions to the equation x^2+14x+38=0 ?
The solutions to the equation x^2+14x+38=0 are x=-7+sqrt(11),x=-7-sqrt(11)
Find the zeros of x^2+14x+38=0
The zeros of x^2+14x+38=0 are x=-7+sqrt(11),x=-7-sqrt(11)