What are the solutions to the equation 15x^2-31x+10=0 ?

The solutions to the equation 15x^2-31x+10=0 are x= 5/3 ,x= 2/5

Find the zeros of 15x^2-31x+10=0

The zeros of 15x^2-31x+10=0 are x= 5/3 ,x= 2/5

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15 x^{2} - 31 x + 10 = 0

x = \frac{5}{3}, x = \frac{2}{5}

Solution steps

15 x^{2} - 31 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 31 ) \pm ( - 31 ) ^{2} - 4 \cdot 15 \cdot 10}{2 \cdot 15}

(- 31)^{2} - 4 \cdot 15 \cdot 10 = 19

x_{1, 2} = \frac{- ( - 31 ) \pm 19}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- ( - 31 ) + 19}{2 \cdot 15}, x_{2} = \frac{- ( - 31 ) - 19}{2 \cdot 15}

x = \frac{- ( - 31 ) + 19}{2 \cdot 15} : \frac{5}{3}

x = \frac{- ( - 31 ) - 19}{2 \cdot 15} : \frac{2}{5}

The solutions to the quadratic equation are:

x = \frac{5}{3}, x = \frac{2}{5}

2 w^{2} + 29 = - 21

s^{2} + 8 s + 16 = 0

(21 - y)^{2} + y^{2} = 221

4.6 x = 4 - x^{2}

- 12 x^{2} + 12 = 0

What are the solutions to the equation 15x^2-31x+10=0 ?
The solutions to the equation 15x^2-31x+10=0 are x= 5/3 ,x= 2/5
Find the zeros of 15x^2-31x+10=0
The zeros of 15x^2-31x+10=0 are x= 5/3 ,x= 2/5