What are the solutions to the equation -12x^2+12=0 ?

The solutions to the equation -12x^2+12=0 are x=1,x=-1

Find the zeros of -12x^2+12=0

The zeros of -12x^2+12=0 are x=1,x=-1

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- 12 x^{2} + 12 = 0

x = 1, x = - 1

Solution steps

- 12 x^{2} + 12 = 0

Move

12

to the right side

- 12 x^{2} = - 12

Divide both sides by

- 12

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

v^{2} - 9 v + 14 = 0

s, h (s) = - 16 s^{2} + 80 s

a = x^{2} - 18 x + 80

x^{2} + 8 x + 16 = 16

x, y = x^{2} - 2 x - 3

What are the solutions to the equation -12x^2+12=0 ?
The solutions to the equation -12x^2+12=0 are x=1,x=-1
Find the zeros of -12x^2+12=0
The zeros of -12x^2+12=0 are x=1,x=-1