What are the solutions to the equation solvefor x,y=x^2-2x-3 ?

The solutions to the equation solvefor x,y=x^2-2x-3 are x=1+sqrt(y+4),x=1-sqrt(y+4)

Find the zeros of solvefor x,y=x^2-2x-3

The zeros of solvefor x,y=x^2-2x-3 are x=1+sqrt(y+4),x=1-sqrt(y+4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

x, y = x^{2} - 2 x - 3

x = 1 + y + 4, x = 1 - y + 4

Solution steps

y = x^{2} - 2 x - 3

Switch sides

x^{2} - 2 x - 3 = y

Move

y

to the left side

x^{2} - 2 x - 3 - y = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 3 - y )}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot (- 3 - y) : 2 y + 4

x_{1, 2} = \frac{- ( - 2 ) \pm 2 y + 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 y + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 y + 4}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 y + 4}{2 \cdot 1} : 1 + y + 4

x = \frac{- ( - 2 ) - 2 y + 4}{2 \cdot 1} : 1 - y + 4

The solutions to the quadratic equation are:

x = 1 + y + 4, x = 1 - y + 4

u^{2} - 4 u + 4 = 0

- 0.6 x^{2} + 14 x + 15 = - 0.4 x + 99

x^{2} + 19 x + 88 = 0

10 x^{2} - x - 11 = 0

x (x + 5) = 36

What are the solutions to the equation solvefor x,y=x^2-2x-3 ?
The solutions to the equation solvefor x,y=x^2-2x-3 are x=1+sqrt(y+4),x=1-sqrt(y+4)
Find the zeros of solvefor x,y=x^2-2x-3
The zeros of solvefor x,y=x^2-2x-3 are x=1+sqrt(y+4),x=1-sqrt(y+4)