What are the solutions to the equation u^2-4u+4=0 ?

The solutions to the equation u^2-4u+4=0 are u=2

Find the zeros of u^2-4u+4=0

The zeros of u^2-4u+4=0 are u=2

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u^{2} - 4 u + 4 = 0

u = 2

Solution steps

u^{2} - 4 u + 4 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 4 = 0

u_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 1}

u = \frac{- ( - 4 )}{2 \cdot 1}

\frac{- ( - 4 )}{2 \cdot 1} = 2

u = 2

The solution to the quadratic equation is:

u = 2

- 0.6 x^{2} + 14 x + 15 = - 0.4 x + 99

x^{2} + 19 x + 88 = 0

10 x^{2} - x - 11 = 0

x (x + 5) = 36

(x + 1)^{2} = 36

What are the solutions to the equation u^2-4u+4=0 ?
The solutions to the equation u^2-4u+4=0 are u=2
Find the zeros of u^2-4u+4=0
The zeros of u^2-4u+4=0 are u=2