What are the solutions to the equation (x+1)^2=36 ?

The solutions to the equation (x+1)^2=36 are x=5,x=-7

Find the zeros of (x+1)^2=36

The zeros of (x+1)^2=36 are x=5,x=-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 1)^{2} = 36

x = 5, x = - 7

Solution steps

(x + 1)^{2} = 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 36 : x = 5

Solve

x + 1 = - 36 : x = - 7

The solutions to the quadratic equation are:

x = 5, x = - 7

5 x^{2} + 4 = x

x, 4 x^{2} - 9 y^{2} = 0

y^{2} - 6 y - 16 = 0

x^{2} + 5 x - 25 = 0

x^{2} + 2 x - 255 = 0

What are the solutions to the equation (x+1)^2=36 ?
The solutions to the equation (x+1)^2=36 are x=5,x=-7
Find the zeros of (x+1)^2=36
The zeros of (x+1)^2=36 are x=5,x=-7