What are the solutions to the equation x^2+5x-25=0 ?

The solutions to the equation x^2+5x-25=0 are x=(-5+5sqrt(5))/2 ,x=(-5-5sqrt(5))/2

Find the zeros of x^2+5x-25=0

The zeros of x^2+5x-25=0 are x=(-5+5sqrt(5))/2 ,x=(-5-5sqrt(5))/2

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x^{2} + 5 x - 25 = 0

x = \frac{- 5 + 5 5}{2}, x = \frac{- 5 - 5 5}{2}

Decimal Notation

x = 3.09016 \dots, x = - 8.09016 \dots

Solution steps

x^{2} + 5 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 25 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 25) = 55

x_{1, 2} = \frac{- 5 \pm 5 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 5 5}{2 \cdot 1}, x_{2} = \frac{- 5 - 5 5}{2 \cdot 1}

x = \frac{- 5 + 5 5}{2 \cdot 1} : \frac{- 5 + 5 5}{2}

x = \frac{- 5 - 5 5}{2 \cdot 1} : \frac{- 5 - 5 5}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 5 5}{2}, x = \frac{- 5 - 5 5}{2}

x^{2} + 2 x - 255 = 0

9 x^{2} + 54 x + 85 = 0

5 x^{2} - 0.8 x = 0

- 2 x^{2} + 1 = - 6

3 x^{2} - 6 x + 5

What are the solutions to the equation x^2+5x-25=0 ?
The solutions to the equation x^2+5x-25=0 are x=(-5+5sqrt(5))/2 ,x=(-5-5sqrt(5))/2
Find the zeros of x^2+5x-25=0
The zeros of x^2+5x-25=0 are x=(-5+5sqrt(5))/2 ,x=(-5-5sqrt(5))/2