What are the solutions to the equation -2x^2+1=-6 ?

The solutions to the equation -2x^2+1=-6 are x=sqrt(7/2),x=-sqrt(7/2)

Find the zeros of -2x^2+1=-6

The zeros of -2x^2+1=-6 are x=sqrt(7/2),x=-sqrt(7/2)

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- 2 x^{2} + 1 = - 6

x = \frac{7}{2}, x = - \frac{7}{2}

Decimal Notation

x = 1.87082 \dots, x = - 1.87082 \dots

Solution steps

- 2 x^{2} + 1 = - 6

Move

1

to the right side

- 2 x^{2} = - 7

Divide both sides by

- 2

x^{2} = \frac{7}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{7}{2}, x = - \frac{7}{2}

3 x^{2} - 6 x + 5

x^{2} = - 4 x - 4

x^{2} - 18 x + 10 = 0

x^{2} - 4 x + 24 = 0

x^{2} - 18 x + 401 = 0

What are the solutions to the equation -2x^2+1=-6 ?
The solutions to the equation -2x^2+1=-6 are x=sqrt(7/2),x=-sqrt(7/2)
Find the zeros of -2x^2+1=-6
The zeros of -2x^2+1=-6 are x=sqrt(7/2),x=-sqrt(7/2)