What are the solutions to the equation x^2-18x+401=0 ?

The solutions to the equation x^2-18x+401=0 are x=9+8sqrt(5)i,x=9-8sqrt(5)i

Find the zeros of x^2-18x+401=0

The zeros of x^2-18x+401=0 are x=9+8sqrt(5)i,x=9-8sqrt(5)i

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x^{2} - 18 x + 401 = 0

x = 9 + 85 i, x = 9 - 85 i

Solution steps

x^{2} - 18 x + 401 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 401}{2 \cdot 1}

Simplify

(- 18)^{2} - 4 \cdot 1 \cdot 401 : 165 i

x_{1, 2} = \frac{- ( - 18 ) \pm 16 5 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 16 5 i}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 16 5 i}{2 \cdot 1}

x = \frac{- ( - 18 ) + 16 5 i}{2 \cdot 1} : 9 + 85 i

x = \frac{- ( - 18 ) - 16 5 i}{2 \cdot 1} : 9 - 85 i

The solutions to the quadratic equation are:

x = 9 + 85 i, x = 9 - 85 i

(6 x - 4) (3 x + 5) = (4 x - 9) (3 x + 5)

x^{2} = \frac{4}{9}

x^{2} = 10 x - 74

12 x^{2} - 320 x + 1600 = 0

2 x + 6 = x^{2}

What are the solutions to the equation x^2-18x+401=0 ?
The solutions to the equation x^2-18x+401=0 are x=9+8sqrt(5)i,x=9-8sqrt(5)i
Find the zeros of x^2-18x+401=0
The zeros of x^2-18x+401=0 are x=9+8sqrt(5)i,x=9-8sqrt(5)i