What are the solutions to the equation n^2-7n-2=0 ?

The solutions to the equation n^2-7n-2=0 are n=(7+sqrt(57))/2 ,n=(7-sqrt(57))/2

Find the zeros of n^2-7n-2=0

The zeros of n^2-7n-2=0 are n=(7+sqrt(57))/2 ,n=(7-sqrt(57))/2

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n^{2} - 7 n - 2 = 0

n = \frac{7 + 57}{2}, n = \frac{7 - 57}{2}

Solution steps

n^{2} - 7 n - 2 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 2) = 57

n_{1, 2} = \frac{- ( - 7 ) \pm 57}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 7 ) + 57}{2 \cdot 1}, n_{2} = \frac{- ( - 7 ) - 57}{2 \cdot 1}

n = \frac{- ( - 7 ) + 57}{2 \cdot 1} : \frac{7 + 57}{2}

n = \frac{- ( - 7 ) - 57}{2 \cdot 1} : \frac{7 - 57}{2}

The solutions to the quadratic equation are:

n = \frac{7 + 57}{2}, n = \frac{7 - 57}{2}

(5 x + 5)^{2} + 3 = 39

12 x^{2} - 204 x + 594 = 0

x, z = 3 x^{2} y + 4 x y^{2}

x^{2} + 7 x + 30 = 0

x, x^{2} - 4 y^{2} = 0

What are the solutions to the equation n^2-7n-2=0 ?
The solutions to the equation n^2-7n-2=0 are n=(7+sqrt(57))/2 ,n=(7-sqrt(57))/2
Find the zeros of n^2-7n-2=0
The zeros of n^2-7n-2=0 are n=(7+sqrt(57))/2 ,n=(7-sqrt(57))/2