What are the solutions to the equation 4x^2+3x=22 ?

The solutions to the equation 4x^2+3x=22 are x=2,x=-11/4

Find the zeros of 4x^2+3x=22

The zeros of 4x^2+3x=22 are x=2,x=-11/4

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4 x^{2} + 3 x = 22

x = 2, x = - \frac{11}{4}

Solution steps

4 x^{2} + 3 x = 22

Move

22

to the left side

4 x^{2} + 3 x - 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 4 ( - 22 )}{2 \cdot 4}

3^{2} - 4 \cdot 4 (- 22) = 19

x_{1, 2} = \frac{- 3 \pm 19}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 3 + 19}{2 \cdot 4}, x_{2} = \frac{- 3 - 19}{2 \cdot 4}

x = \frac{- 3 + 19}{2 \cdot 4} : 2

x = \frac{- 3 - 19}{2 \cdot 4} : - \frac{11}{4}

The solutions to the quadratic equation are:

x = 2, x = - \frac{11}{4}

9 + 8 x - x^{2}

2 0^{2} + 1 5^{2} = c^{2}

4 x^{2} = 5

m^{2} - 7 m + 6 = 0

(x + 3) (x - 3) = 0

What are the solutions to the equation 4x^2+3x=22 ?
The solutions to the equation 4x^2+3x=22 are x=2,x=-11/4
Find the zeros of 4x^2+3x=22
The zeros of 4x^2+3x=22 are x=2,x=-11/4