What are the solutions to the equation 5n^2-18n+12=0 ?

The solutions to the equation 5n^2-18n+12=0 are n=(9+sqrt(21))/5 ,n=(9-sqrt(21))/5

Find the zeros of 5n^2-18n+12=0

The zeros of 5n^2-18n+12=0 are n=(9+sqrt(21))/5 ,n=(9-sqrt(21))/5

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5 n^{2} - 18 n + 12 = 0

n = \frac{9 + 21}{5}, n = \frac{9 - 21}{5}

Decimal Notation

n = 2.71651 \dots, n = 0.88348 \dots

Solution steps

5 n^{2} - 18 n + 12 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 5 \cdot 12}{2 \cdot 5}

(- 18)^{2} - 4 \cdot 5 \cdot 12 = 221

n_{1, 2} = \frac{- ( - 18 ) \pm 2 21}{2 \cdot 5}

Separate the solutions

n_{1} = \frac{- ( - 18 ) + 2 21}{2 \cdot 5}, n_{2} = \frac{- ( - 18 ) - 2 21}{2 \cdot 5}

n = \frac{- ( - 18 ) + 2 21}{2 \cdot 5} : \frac{9 + 21}{5}

n = \frac{- ( - 18 ) - 2 21}{2 \cdot 5} : \frac{9 - 21}{5}

The solutions to the quadratic equation are:

n = \frac{9 + 21}{5}, n = \frac{9 - 21}{5}

x^{2} - 10 x + 25 = 144

x, - 11 x^{2} + 132 x + 17 y^{2} - 136 y - 124 = 0

(2 x - 7)^{2} = (x - 4)^{2} + (2 x + 3) (2 x - 5)

(x - 4)^{2} = - 25

4 x^{2} + 5 x = 8

What are the solutions to the equation 5n^2-18n+12=0 ?
The solutions to the equation 5n^2-18n+12=0 are n=(9+sqrt(21))/5 ,n=(9-sqrt(21))/5
Find the zeros of 5n^2-18n+12=0
The zeros of 5n^2-18n+12=0 are n=(9+sqrt(21))/5 ,n=(9-sqrt(21))/5