What are the solutions to the equation x^2-10x+25=144 ?

The solutions to the equation x^2-10x+25=144 are x=17,x=-7

Find the zeros of x^2-10x+25=144

The zeros of x^2-10x+25=144 are x=17,x=-7

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x^{2} - 10 x + 25 = 144

x = 17, x = - 7

Solution steps

x^{2} - 10 x + 25 = 144

Move

144

to the left side

x^{2} - 10 x - 119 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( - 119 )}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot (- 119) = 24

x_{1, 2} = \frac{- ( - 10 ) \pm 24}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 24}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 24}{2 \cdot 1}

x = \frac{- ( - 10 ) + 24}{2 \cdot 1} : 17

x = \frac{- ( - 10 ) - 24}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 17, x = - 7

x, - 11 x^{2} + 132 x + 17 y^{2} - 136 y - 124 = 0

(2 x - 7)^{2} = (x - 4)^{2} + (2 x + 3) (2 x - 5)

(x - 4)^{2} = - 25

4 x^{2} + 5 x = 8

X^{2} + 2 X + 1 = 0

What are the solutions to the equation x^2-10x+25=144 ?
The solutions to the equation x^2-10x+25=144 are x=17,x=-7
Find the zeros of x^2-10x+25=144
The zeros of x^2-10x+25=144 are x=17,x=-7