What are the solutions to the equation X^2+2X+1=0 ?

The solutions to the equation X^2+2X+1=0 are X=-1

Find the zeros of X^2+2X+1=0

The zeros of X^2+2X+1=0 are X=-1

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X^{2} + 2 X + 1 = 0

X = - 1

Solution steps

X^{2} + 2 X + 1 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 1 = 0

X_{1, 2} = \frac{- 2 \pm 0}{2 \cdot 1}

X = \frac{- 2}{2 \cdot 1}

\frac{- 2}{2 \cdot 1} = - 1

X = - 1

The solution to the quadratic equation is:

X = - 1

x^{2} + x + 15 = 0

x^{2} - 16 x = 17

12 x^{2} - 20 x + 7 = 0

3 r^{2} - 2 r - 1 = 0

(x + 4) (3 x - 7) = 0

What are the solutions to the equation X^2+2X+1=0 ?
The solutions to the equation X^2+2X+1=0 are X=-1
Find the zeros of X^2+2X+1=0
The zeros of X^2+2X+1=0 are X=-1