What are the solutions to the equation (x+4)(3x-7)=0 ?

The solutions to the equation (x+4)(3x-7)=0 are x=-4,x= 7/3

Find the zeros of (x+4)(3x-7)=0

The zeros of (x+4)(3x-7)=0 are x=-4,x= 7/3

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(x + 4) (3 x - 7) = 0

x = - 4, x = \frac{7}{3}

Solution steps

(x + 4) (3 x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or 3 x - 7 = 0

Solve

x + 4 = 0 : x = - 4

Solve

3 x - 7 = 0 : x = \frac{7}{3}

The solutions to the quadratic equation are:

x = - 4, x = \frac{7}{3}

- 12 x^{2} + 24 x = 0

x^{2} - 8 x + 5

4 x^{2} - 3 x - 22 = 0

m^{2} - 4 m - 5 = 0

6 x^{2} - 12 x + 24 = 0

What are the solutions to the equation (x+4)(3x-7)=0 ?
The solutions to the equation (x+4)(3x-7)=0 are x=-4,x= 7/3
Find the zeros of (x+4)(3x-7)=0
The zeros of (x+4)(3x-7)=0 are x=-4,x= 7/3